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5 points by pg 6120 days ago | link | parent

1 is not a bad idea. I may do this. But you'd still need apply for use as an argument.

2 wouldn't work because you couldn't redefine a var that was a hash table to be a fn.

4 is zap.



1 point by im 6119 days ago | link

Re. 2: That's true. In general, it would mean you could only define names with =, not objects in general. The other option would be to leave = as is and change def to have PLT-esque behavior, but then we're away from the whole "reducing the number of operators" idea. (And whether (def f (args) ....) or (def (f args) ... is better is is kind of a religious debate, though my religion favors the second as more closely resembling how f is actually used later on.)

Re. 4: It might be zap, if you could write something like ((zap f) x y z) or (zap f x y z), instead of (= x (f x y z)). In fact, though, (f! x y z) is equivalent to (zap [f _ y z] x), and f! alone is equivalent to (fn args (= (car args) (apply f args))). (I couldn't think of a more concise expression using zap.) I think I'd much rather pass f! than (fn args (= (car args) (apply f args))) as an argument.

Actually, I might be mistaken, and I don't have the code (or my own machine) in front of me at the moment. Can you write (zap f x y z) right now?

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2 points by im 6118 days ago | link

After testing it, I find that (zap f x y z) does in fact act as (= x (f x y z)). And, if implicit currying is added as per someone else's suggestion, (zap f) will act as (fn args (= (car args) (apply f args))). So that works, then.

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